Find the maximum value and its location from a matrix using two nested loops
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Hi,
Right now I have this matrix K
K =
-3 -8 6 -3 -8 6 9 24 -18
-5 10 -9 -5 10 -9 15 -30 27
8 4 9 8 4 9 -24 -12 -27
-9 -24 18 12 32 -24 3 8 -6
-15 30 -27 20 -40 36 5 -10 9
24 12 27 -32 -16 -36 -8 -4 -9
9 24 -18 -15 -40 30 0 0 0
15 -30 27 -25 50 -45 0 0 0
-24 -12 -27 40 20 45 0 0 0
I wonder how I can use two nested loops to find the maximum number and its location from this matrix.
It would be great if anyone can help me with this
Thank you very much :)
採用された回答
sixwwwwww
2013 年 12 月 8 日
編集済み: sixwwwwww
2013 年 12 月 8 日
you can do it as follow:
MaxValue = -Inf;
row = 0;
column = 0;
for i = 1:size(K, 1)
for j = 1:size(K, 2)
if K(i, j) > MaxValue
MaxValue = K(i, j);
row = i;
column = j;
end
end
end
6 件のコメント
Image Analyst
2013 年 12 月 8 日
But you didn't ask for other ways - you rigidly specified the way. The other, more MATLAB-ish way would be to use the max() function. Look at the two arguments it returns. You might also find ind2sub() helpful,
Alexandra Vaupotic
2021 年 2 月 8 日
編集済み: Alexandra Vaupotic
2021 年 2 月 8 日
How could you make this a function with an output of the Max value?
その他の回答 (1 件)
Khalid Mojallid
2019 年 3 月 26 日
MaxValue = -Inf;
row = 0;
column = 0;
for i = 1:size(K, 1)
for j = 1:size(K, 2)
if K(i, j) > MaxValue
MaxValue = K(i, j);
row = i;
column = j;
end
end
end
1 件のコメント
Nathan Blais
2019 年 10 月 3 日
I'm guessing K would be the vector we are trying to find the max value for?
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