resample gives dimension error
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When I use the resample function, I get a dimension error. Here is the example used in the MATLAB help file, with the output:
fs1 = 10; % Original sampling frequency in Hz
t1 = 0:1/fs1:1; % Time vector
x = t1; % Define a linear sequence
y = resample(x,3,2); % Now resample it
Error using + Matrix dimensions must agree.
Error in firls (line 161) b = b + (F(s+1)*(m*F(s+1)+b1)*sinc(2*k*F(s+1)) ...
Error in resample (line 85) h = p*firls( L-1, [0 2*fc 2*fc 1], [1 1 0 0]).*kaiser(L,bta)' ;
採用された回答
Wayne King
2013 年 12 月 4 日
I'm not sure if you have a non-MathWorks' (modified) version of firls(), but the code you entered above should work:
fs1 = 10;
t1 = 0:1/fs1:1; % Time vector
x = t1; % Define a linear sequence
y = resample(x,3,2); % Now resample it
Can you clear you workspace and copy and paste the above?
If you enter
>>which firls
Do you get something back like:
matlab\toolbox\signal\signal\firls.m
Also, which version of MATLAB are you using?
その他の回答 (6 件)
Thomas Carroll
2013 年 12 月 4 日
0 投票
1 件のコメント
Wayne King
2013 年 12 月 4 日
Thomas, I have to look around for a Mac to try this on, but it works on Windows and Linux R2013b. This is very strange- I'd be very surprised that this behavior would differ on Mac
I'm assuming if you use which for resample.m you also get a path like above?
Wayne King
2013 年 12 月 4 日
編集済み: Wayne King
2013 年 12 月 4 日
Let's look at all the functions called by your code. Execute the following:
profile on -history
fs1 = 10;
t1 = 0:1/fs1:1; % Time vector
x = t1; % Define a linear sequence
y = resample(x,3,2); % Now resample it
p = profile('info');
for n = 1:size(p.FunctionHistory,2)
if p.FunctionHistory(1,n)==0
str = 'entering function: ';
else
str = ' exiting function: ';
end
disp([str p.FunctionTable(p.FunctionHistory(2,n)).FunctionName]);
end
Now you should get a list like this:
entering function: resample
entering function: rat
exiting function: rat
entering function: firls
entering function: signal\private\firchk
exiting function: signal\private\firchk
entering function: sinc
exiting function: sinc
entering function: sinc
exiting function: sinc
entering function: sinc
exiting function: sinc
entering function: sinc
exiting function: sinc
exiting function: firls
entering function: kaiser
entering function: signal\private\check_order
exiting function: signal\private\check_order
exiting function: kaiser
entering function: upfirdn
entering function: upfirdn>validateinput
entering function: intmax
exiting function: intmax
exiting function: upfirdn>validateinput
entering function: signal\private\upfirdnmex
exiting function: signal\private\upfirdnmex
exiting function: upfirdn
exiting function: resample
Is it possible that you have a local copy of one of those functions? like upfirdn, etc. ?
1 件のコメント
Wayne King
2013 年 12 月 4 日
The code should work on Mac -- just confirmed.
Thomas Carroll
2013 年 12 月 4 日
1 件のコメント
Wayne King
2013 年 12 月 4 日
I would, yes. There's no reason it should not work
Thomas Carroll
2013 年 12 月 4 日
0 投票
4 件のコメント
Wayne King
2013 年 12 月 4 日
did you attach it here? I don't see the attachment. Yes, I can diff it.
Thomas Carroll
2013 年 12 月 4 日
Thomas Carroll
2013 年 12 月 5 日
Wayne King
2013 年 12 月 5 日
I agree this is not optimal. Thomas, can you contact tech support about this question. It sounds to me like there should be some investigating done here. You can refer them to this thread. I think you'll find them very responsive.
Jenny
2015 年 2 月 26 日
This error could be caused by a third party toolbox or function shadowing the FIRLS function.
If you run the command:
>> which -all firls
it should list only MATLAB functions. If there's another FIRLS function listed, not provided by MathWorks, then uninstall the toolbox or rename your function to something else.
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