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Spectrogram windowing- why do the 2 methods generate different graphs?

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Win
Win 2013 年 11 月 28 日
コメント済み: Win 2013 年 11 月 28 日
Method 1 spectrogram(x,128,16,128,FS)
Method 2 w = window(@hamming,128); [S,F,T,P] = spectrogram(x,w,16,128,FS);
Since I cannot change the window type in method 1, I am using method 2. I would like to know why there is a BIG difference in the figures generated.

採用された回答

Wayne King
Wayne King 2013 年 11 月 28 日
編集済み: Wayne King 2013 年 11 月 28 日
That is a different question. The answer to that question is that calling spectrogram() with no output arguments is the same as providing the 'xaxis' option for FREQLOCATION (this is explained in the help).
That means that instead of having frequency on the y-axis as your second figure does and my figures too, you have frequency on the x-axis and time on the y-axis.
  4 件のコメント
Wayne King
Wayne King 2013 年 11 月 28 日
yes, you can manipulate the color axis by setting limits and or manipulating the color map. Also, you should overlap your windows more.
For example:
[S,F,T,P] = spectrogram(x,128,64,128,FS);
surf(T,F,10*log10(P),'edgecolor','none'); axis tight;
view(0,90); caxis([-90 5])
Win
Win 2013 年 11 月 28 日
Ok, that helps, thanks! :)

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その他の回答 (2 件)

Wayne King
Wayne King 2013 年 11 月 28 日
Are you sure you are using MathWorks' version of spectrogram() and/or hamming()? Because I see no difference at all (and there should not be)
x = randn(1000,1);
FS = 1;
w = window(@hamming,128); [S,F,T,P] = spectrogram(x,w,16,128,FS);
[S1,F1,T1,P1] = spectrogram(x,128,16,128,FS);
isequal(S,S1) % returns a 1
isequal(P,P1) % also returns a 1
If you enter
>>which spectrogram
and
>>which hamming
Do you get paths that end in:
matlab\toolbox\signal\signal
  2 件のコメント
Win
Win 2013 年 11 月 28 日
I am using the spectrogram function but in the documentation it is said that hamming is the default window. Hence I tried to reproduce it using the second function. Here are my codes:
clear all; FS = 100; w1=2; w2=5; w3=40; i=1; for t=0:1/FS:10
if t<=2
x(i)=5*sin(2*pi*w1*t);
end
if (t>2)&& (t<=4)
x(i)=2*sin(2*pi*w2*t);
end
if (t>4)&& (t<=10)
x(i)=sin(2*pi*w3*t);
end
i=i+1;
end
%Method 1
%spectrogram(x,128,16,128,FS)
%Method 2
w = window(@hamming,128);
[S,F,T,P] = spectrogram(x,w,16,128,FS);
figure
surf(T,F,10*log10(P),'edgecolor','none'); axis tight;
view(0,90);
Win
Win 2013 年 11 月 28 日
On typing which spectrogram I get: C:\Program Files\MATLAB\R2012a\toolbox\signal\signal\spectrogram.m and on typing which hamming I get C:\Program Files\MATLAB\R2012a\toolbox\signal\signal\hamming.m

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Wayne King
Wayne King 2013 年 11 月 28 日
編集済み: Wayne King 2013 年 11 月 28 日
Here I use your signal and they are identical:
FS = 100;
w1=2; w2=5; w3=40;
t=0:1/FS:10;
dt = 1/FS;
x = zeros(size(t));
idx1 = 2/dt+1;
idx2 = idx1+1:(4/dt+1);
idx3 = (4/dt+2):length(t);
x(1:idx1) = 5*sin(2*pi*w1*t(1:idx1));
x(idx2) = 2*sin(2*pi*w2*t(idx2));
x(idx3) = sin(2*pi*w3*t(idx3));
w = window(@hamming,128); [S,F,T,P] = spectrogram(x,w,16,128,FS);
[S1,F1,T1,P1] = spectrogram(x,128,16,128,FS);
isequal(S,S1) % returns a 1
isequal(P,P1) % also returns a 1
figure
surf(T,F,10*log10(P),'edgecolor','none'); axis tight;
view(0,90);
figure
surf(T,F,10*log10(P1),'edgecolor','none'); axis tight;
view(0,90);
And yes Hamming is the default window.
  4 件のコメント
Win
Win 2013 年 11 月 28 日
Ok, maybe I worded my question wrongly
On using the following lines: w = window(@hamming,128); [S,F,T,P] = spectrogram(x,w,16,128,FS); figure surf(T,F,10*log10(P),'edgecolor','none'); axis tight; view(0,90);
I get the figure below. I wanted to know why it's different to the figure above.
Win
Win 2013 年 11 月 28 日
Ignoring the swap in axes of course as that can be easily fixed.

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