Function of many input arguments returns only one value

I have this function:

n = [0 :1: 40], x = 1.0,

v = ((sin(x + 2.^-n) + cos(3*x + 2.^-n)) - (sin(x) + cos(3*x)))/(2.^-n)

It only displays the result for the first value of n and I would like to get the results for all n from 0 to 40. How do I do this? I tried to modify this in many ways but nothing seems to work...

Answer 1

[Azzi Abdelmalek]

You missed ./

n = [0 :1: 40], x = 1.0,
v = sin(x + 2.^-n) + cos(3*x + 2.^-n) -(sin(x) + cos(3*x))./(2.^-n)