problem in converting double Array into character?

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Behrad kiani
Behrad kiani 2013 年 10 月 26 日
編集済み: Cedric 2013 年 10 月 26 日
There is an Array with double type and I want to convert it into character but there is a problem and that is the number of each cell contains the number of character. for example I need to convert 49 to 1 in character. i write the code below but it doesn’t work at all.it just to show you what I mean. Value of a Array is:
a(1)=49
a(2)=49
a(3)=52
a(4)=50
%code
z(1)=num2str(a(1));
z(2)=num2str(a(2));
z(3)=int2str(a(3));
numberplate = char(str2num(z(1)))+char(str2num(z(2)))+char(str2num(z(3))+ char(str2num(z(4))
%end of code
And the value of numberplate should be numberplate==’1132’. thanks

採用された回答

Cedric
Cedric 2013 年 10 月 26 日
編集済み: Cedric 2013 年 10 月 26 日
Just "type cast" to char:
>> numberplate = char(a)
numberplate =
1132
In your code, you convert to string, then to numeric again, then you "type cast". You can go directly for the latter.

その他の回答 (1 件)

Azzi Abdelmalek
Azzi Abdelmalek 2013 年 10 月 26 日
You should use cell array
clear
a(1)=49
a(2)=49
a(3)=152
a(4)=50
z{1}=num2str(a(1));
z{2}=num2str(a(2));
z{3}=int2str(a(3));
z{4}=int2str(a(4));
numberplate = char(str2num(z{1}))+char(str2num(z{2}))+char(str2num(z{3}))+ char(str2num(z{4}))

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