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JK


Last seen: 7日 前 |  2017 年からアクティブ

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質問


generation of 2D array of circular ring
I am looking for a way to generate 2D array of circular ring in retangular coordinate. outer diameter (D) inner diameter (d) ...

1年以上 前 | 2 件の回答 | 0

2

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質問


summation of a matrix inside circle
Hello, I have 2D NxN matrix array and I want to get summation of data inside circle from center. The size of circle is varied...

3年以上 前 | 1 件の回答 | 0

1

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質問


conditioning array with complex number
I would like to apply a condition to make certain complex numbers to zero. condition: if complex number * conj(complex number...

3年以上 前 | 1 件の回答 | 0

1

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質問


matrix insert with a condition
can you help me insert m x n matrix into M x N matrix with a condition that is without zero. starting location is (x,y) M x N ...

6年弱 前 | 1 件の回答 | 0

1

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質問


matrix manipulation - replacing partial matrix subsets in main matrix ???
I have two matrices : one is NxM and other is nxm (N>n, M>m). I would like to insert nxm matrix at location starting at (x,y) b...

6年弱 前 | 1 件の回答 | 0

1

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質問


Simulation of RF amplifier with passband using square pulse
I am trying to simulate amplification of square pulse thru RF amplifier with a finite bandwidth (low frequency & high frequency ...

6年以上 前 | 0 件の回答 | 0

0

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質問


array manipulation such as [ 1 2 5 7 3 .... ] --> [ 1 1 1 ... 2 2 2 ... 5 5 5 ... 7 7 7 ... 3 3 3 ... .... ].
Using A = [ 1 2 5 7 3 .... ], I would like to create B = [ 1 1 1 ... 2 2 2 ... 5 5 5 ... 7 7 7 ... 3 3 3 ... ......

7年以上 前 | 2 件の回答 | 0

2

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trying to make data set from non-equally spaced to eqally spaced
I have two sets of data which are not equally spaced. What I am trying to do is to use interpolation to get an equally space...

7年以上 前 | 1 件の回答 | 0

1

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Error : Interpolation methods require data where the values in X are unique.
I am trying to do a simple interpolation. However I got an error message " Interpolation methods require data where the values ...

7年以上 前 | 1 件の回答 | 0

1

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質問


How to use "fzero" command with a variable(s)?
format long; lp_upper='besselj(1,x)/besselj(0,x)-besselk(1,sqrt(3.543149609311796^2-x^2))/besselk(0,sqrt(3.543149609311...

約8年 前 | 0 件の回答 | 0

0

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