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Sara


2012 年からアクティブ

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optimize code in running time
Hi, is there any suggestion that how can I optimize the code in running time below. Thanks in advance lenx=length(x); ...

12年以上 前 | 0 件の回答 | 0

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array operations consuming lower time
Hi, we have an array x, I would like to do such a operation on it. It can be possible to implement it another way that consumes...

12年以上 前 | 2 件の回答 | 0

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solving equation in matlab
Hi. I want to find the l and mu , by the code below. I have linked the image that indicates l and mu how they used in equatio...

12年以上 前 | 0 件の回答 | 0

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Integrals function computing accelerating
Hi Guys , - trapz - cumtrapz function int = Fcn_integ(x,k,dt) x ... Signal to integration k ... Numb...

12年以上 前 | 1 件の回答 | 0

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optimize code regarding for loop
Hallo : if k <= 0 int = x ; return end int = zeros(1,length(x)); c=(k-1)/fa...

12年以上 前 | 0 件の回答 | 0

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accelerating code , scalar operations
Hi Guys, if k <= 0 int = x ; return end int = zeros(1,length(x)); c=(k-1)/factorial(k-1); dth2=...

12年以上 前 | 0 件の回答 | 0

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accelerating code in matlab - for loop
Hi Guys, int = zeros(1,length(x)); if k <= 0 int = x ; return end for n = 3:lengt...

12年以上 前 | 2 件の回答 | 0

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redefine array in for loop
Hi Guys, for n = 3:length(x) y1 = x(2:n) ; t1 = ((n-2):-1:0)*dt ; % y2 = x(1:n-1) ; y2 = y1 -...

12年以上 前 | 1 件の回答 | 0

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simplyfing computations in arrays
int = zeros(1,length(x)); for n = 3:length(x) y1 = x(2:n) ; t1 = n*dt - (2*dt:dt:n*dt) ; y2 = x(1:n-1)...

12年以上 前 | 2 件の回答 | 0

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SYNTAX MATLAB
y1 = x(2:n) ; t1 = n*dt - (2*dt:dt:n*dt) could anyone tell me what is the meaning of the these commands? The syntax of...

12年以上 前 | 1 件の回答 | 0

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for loop another way to implement it
Is there any way to replace using for loop here by another way to do the desired? x = zeros(length(v0),2)...

12年以上 前 | 0 件の回答 | 0

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Index exceeds matrix dimensions.
for the code below I received the error index exceeds.. I do not know how can I fix it. x = zeros( 2,length(v0) ) ; ...

12年以上 前 | 1 件の回答 | 0

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