Routh-Hurwitz stability criterion identifies the conditions when the poles of a polynomial cross into the right
hand half plane and hence would be considered as unstable in control engineering.
Farzad Sagharchi (2020). Routh-Hurwitz stability criterion (https://www.mathworks.com/matlabcentral/fileexchange/17483-routh-hurwitz-stability-criterion), MATLAB Central File Exchange. Retrieved .
Cons: It cannot generate such special cases.
It doesn't work well with [1 0 4 0 0 3 0 2]. I'm not able to do it by hand either ...
عالی . سپاس فراوان
I want to solve routh stability with an unknown K. How can ı do that ?
Is there a way we could do this symbolically? Like for a parametrized system.
Awesome!!! Thank you so much for this :)
Works like a charm. Saved me lots of time. Thanks!!!!
How to use it when you need use hurwitz criterion
Awesome, Thank you
thanks a lot
Thank you very much sir!
thx a lot!!!
Great work, btw I would love to know determining Acceptable Gain Values,K? How to change/add the coding?
Thanks a lot
Thanks a lot . It works perfect
واقعاً عالی بود داداش ممنون :-)
داداش دمت گرم
داداش دمت گرم
Thankx for sharing great job
Cool. Thanks for sharing.
Cannot deal with special case when all elements in a row is 0. Try [1 0 7 0 5 0 2 0].
how can i get the criterion with a variable for example , [1 28 356 1952 5248 1000*kc]??
thank you very much for sharing.
sotty ,the code is working good
thanks for the code but it's buggy as mentiond above , try the following vector [1 4 3 12]
The program is buggy and not accurate. Try [1 1 2 24] which is an example of Dorf control text book. Compare your result with this file:
and compare the result.
very good but how I can operate m-file in command windows
please help me in this
@ J. Palacio
please explain more ! the result and algorithm both are correct.
@ Azeem A
numbers after precision isn't important , just changing sign of the first column in important.
accurate and works great. only issue is that for larger numbers, it uses scientific notation and as a result some precision is lost.
the Routh Hurwitz table returns by this algorithm is not the correct one and it uses a very big value of epsilon for one of the special cases.
Very good. And very simple to use. Good job!
This Is The Best At The First!!!
good job and thank u for sharing
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