Problem 52669. Count the primes in Collatz sequences
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I notice that p=isprime(x) can be a lot slower than p=ismember(x,primes(max(x))); for x=1:1e7, the former takes about 100 seconds and the latter takes about 0.1 seconds.
Nice observation. I'll keep that one in mind.
Actually for the first case (seed n = 1), the answer should be 1 and not 0, since the corresponding Collatz sequence is the loop (1, 4, 2), should'nt it be ?
Ok I suppose we don't count the special case of this infinite loop since we do have to stop the sequence at a point ! (1)
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