Problem 365. Numbers with prime factors 2, 3 and 5.

Created by elias GR

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497 Solutions
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Last Solution submitted on Nov 30, 2020

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3 Comments

Michael on 25 Mar 2020

The problem statement should specify that i, j, and k are non-negative integers or the number of answers becomes infinite.

Michael on 25 Mar 2020

Also, why is 1 not included in all of the answers. 2^0*3^0*5^0 = 1

Rafael S.T. Vieira on 16 Jul 2020

This problem requests the set of hamming numbers without the number one for some reason. https://rosettacode.org/wiki/Hamming_numbers

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Problem 365. Numbers with prime factors 2, 3 and 5.

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Problem 365. Numbers with prime factors 2, 3 and 5.

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Problem Recent Solvers159

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