Problem 351. Back to basics 8 - Matrix Diagonals

[1:4] ->

1 0 0 0
0 2 0 0
0 0 3 0
0 0 0 4

Solution Comments

Problem Recent Solvers920

Suggested Problems

• Clean the List of Names

  1714 Solvers

• Insert zeros into vector

  772 Solvers

• 07 - Common functions and indexing 2

  408 Solvers

• Length of the hypotenuse

  13597 Solvers

• Divisible by 2

  559 Solvers

More from this Author39

• Back to basics 9 - Indexed References

  439 Solvers

• Back to basics 18 - justification

  198 Solvers

• Back to basics 25 - Valid variable names

  323 Solvers

• 2 b | ~ 2 b

  394 Solvers

• Back to basics 24 - Symbolic variables

  143 Solvers