Problem 282. Circle and Quadratic

Created by Matt Fig

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170 Solutions
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Last Solution submitted on Apr 05, 2022

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2 Comments

2 Comments

Gunther S on 14 Feb 2012

the visualisation has an error, it should be

C = @(x) real(-sqrt(R^2-(x-T(1)).^2) + T(2)); % Lower half circle

Matt Fig on 16 Feb 2012

Thanks Gunther. The function does produce the correct graphic, but only when T(1)=0 as in my example.

Solution Comments

Solution 34572

2 Comments

2 Comments

Trung Duong on 9 Feb 2012

Is there any special in Test 3?

Austin Senerchia on 5 Apr 2022

x(1) = -b/(2a)
x(2) = (aR^2) - (3/4)*a - (1/4)(b^2/a) + c

why is this not right? it's close

Solution 34498

2 Comments

2 Comments

Trung Duong on 9 Feb 2012

don't know why the assertions fail.
The solution is correct.

Matt Fig on 9 Feb 2012

If you look at the example posted in the problem description, you will see that the return argument should be a two element row vector.

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Problem 282. Circle and Quadratic

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Problem 282. Circle and Quadratic

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