Problem 252. Project Euler: Problem 16, Sums of Digits of Powers of Two

Created by @bmtran (Bryant Tran)

Solve Later

2^15 = 32768 and the sum of its digits is 3 + 2 + 7 + 6 + 8 = 26.

What is the sum of the digits of the number 2^N?

Thanks to Project Euler Problem 16.

Solve

Solution Stats

343 Solutions
64 Solvers

Last Solution submitted on Feb 17, 2020

Last 200 Solutions

Problem Comments

1 Comment

1 Comment

@bmtran (Bryant Tran) on 4 Feb 2012

added a test case to make it a wee bit harder

Solution Comments

Solution 216618

1 Comment

1 Comment

Harish Maradana on 13 Mar 2013

function y = pow2_sumofdigits(x)
number = sym(2^x);
n = char(number);
y = 0;
for i = 1:length(n)
y = y + str2double(n(i));
end
end
this code gives exact results on my mechine but not work in cody show error
Error: License checkout failed.
License Manager Error -5
Cannot find a license for Symbolic_Toolbox.
Troubleshoot this issue by visiting:
http://www.mathworks.com/support/lme/R2013a/5
Diagnostic Information:
Feature: Symbolic_Toolbox
License path: 13501@10.206.97.41:13501@10.10.207.33:/tmp/matlabpref/.matlab/R2013a_licenses:/opt/mlsedu/matlab/R2013a/licenses/license.dat:/opt/mlsedu/matlab/R2013a/licenses
Licensing error: -5,0.

please help me ...........

Problem Recent Solvers64

Problem Tags

big integer digits project euler

Problem 252. Project Euler: Problem 16, Sums of Digits of Powers of Two

Solution Stats

Last 200 Solutions

Problem Comments

Solution Comments

Problem Recent Solvers64

Suggested Problems

More from this Author56

Problem Tags

Problem 252. Project Euler: Problem 16, Sums of Digits of Powers of Two

Solution Stats

Last 200 Solutions

Problem Comments

Solution Comments

Problem Recent Solvers64

Suggested Problems

More from this Author56

Problem Tags

Players