Tanya, you like triangles.
Good one
Nice one
Pythagoras theorem
These are interesting
a = sqrt(c^2-b^2);
good question
this isn't a calculation!
lol
what the
ez
test_1 a=sqrt(3) is longer than b=1
the good solution would be
a= min(sqrt(c^2 -b^2),b)
instead
regexp cheat
Kudos for finding this solution - it did indeed meet all the test cases, but wasn't quite what I had in mind! I will add a new test.
5921 Solvers
1632 Solvers
Project Euler: Problem 1, Multiples of 3 and 5
1571 Solvers
Back to basics 23 - Triangular matrix
647 Solvers
Are all the three given point in the same line?
280 Solvers
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