This is a shamless answer,I admit...But the explicit recurrence relation is insanely slow,hope to see you guys solve this problem more efficient.
I prefer g(end+1:end+g(gptr))=gptr; to usage of repmat. My machine to solve 1234567 takes 48msec vs 15.4 sec using repmat. repmat has a performance issue with large column replication. Unfortunately score is code size and not time.
totally agree (not to mention the entire 'growing inside a loop' uglyness), cody style is very far from any reasonable coding standard...
That's very interesting. The time difference on my (presumably much older) version of MATLAB is much less. Your method gives me an average time of about 18.8 sec, while repmat gives me an average time of 19.5 sec.
May you give a short explanation on this solution?
This is the asymptotic expression of nth term based on the golden ratio. See http://en.wikipedia.org/wiki/Golomb_sequence
Return a list sorted by number of occurrences
Remove the air bubbles
Check to see if a Sudoku Puzzle is Solved
Back to basics 26 - Keywords
Find the next Fibonacci number
Rewrite setdiff to account for non-unique values
Break it up! Break it up!
Give me Hamming on five, hold the mayo
Lowest sum from a group of digits
I've got the power! (Inspired by Project Euler problem 29)
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