Problem 1092. Decimation

Created by James

Solve Later

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When dealing to the Roman Army, the term decimate meant that the entire unit would be broken up into groups of ten soldiers, and lots would be drawn. The person who was unlucky enough to draw the short straw would be executed by the other nine members of his group.The bloodthirsty Roman Centurion Carnage Maximus decided to apply this to his prisoners, with a few gruesome differences. Rather than kill every tenth prisoner and allow the rest to live, he is going to leave only one prisoner alive and kill all of the others. Instead of killing every tenth prisoner, he chooses a number (kill_every). If kill_every=3, he kills every third prisoner. If kill_every=5, he kills every fifth prisoner. He always chooses a number between 2 and the number of prisoners he has, and this process will be repeated until there is only one prisoner left. For example, if there are 10 prisoners, and kill_every=3First iteration: 1 2 3 4 5 6 7 8 9 101-2-3 4-5-6 7-8-9 10Prisoners 3, 6 and 9 will be killed.Second iteration: 1 2 4 5 7 8 10Because Prisoner 10 was counted during the first iteration, the executions
will proceed as such: 10-1-2 4-5-7 8-10, so prisoners 2 and 7 will be killedThird iteration: 1 4 5 8 10
8-10-1 4-5-8 10, so prisoners 1 and 8 executed.Fourth Iteration: 10-4-5 10
Prisoner 5 is executed.Fifth iteration: 10-4 10
Prisoner 10 is executedSince the sole survivor is prisoner 4, he is released.You are an unlucky prisoner caught by Carnage Maximum. Prior to lining up the prisoners, he reveals the number of prisoners he has and his value of kill_every for the day. Your job is to figure out which prisoner you need to be in order to survive. Write a MATLAB script that takes the values of num_prisoners and kill_every. The output will be survivor, which is the position of the person who survives. If you write your script quickly enough, that person will be you.Good luck!

When dealing to the Roman Army, the term decimate meant that the entire unit would be broken up into groups of ten soldiers, and lots would be drawn.  The person who was unlucky enough to draw the short straw would be executed by the other nine members of his group.

The bloodthirsty Roman Centurion Carnage Maximus decided to apply this to his prisoners, with a few gruesome differences.  Rather than kill every tenth prisoner and allow the rest to live, he is going to leave only one prisoner alive and kill all of the others.  Instead of killing every tenth prisoner, he chooses a number (kill_every).  If kill_every=3, he kills every third prisoner.  If kill_every=5, he kills every fifth prisoner.  He always chooses a number between 2 and the number of prisoners he has, and this process will be repeated until there is only one prisoner left.  For example, if there are 10 prisoners, and kill_every=3

First iteration: 1 2 3 4 5 6 7 8 9 10

1-2-3 4-5-6 7-8-9 10

Prisoners 3, 6 and 9 will be killed.

Second iteration: 1 2 4 5 7 8 10

Because Prisoner 10 was counted during the first iteration, the executions
will proceed as such: 10-1-2 4-5-7 8-10, so prisoners 2 and 7 will be killed

Third iteration: 1 4 5 8 10
8-10-1 4-5-8 10, so prisoners 1 and 8 executed.

Fourth Iteration:  10-4-5 10
Prisoner 5 is executed.

Fifth iteration:  10-4 10
Prisoner 10 is executed

Since the sole survivor is prisoner 4, he is released.

You are an unlucky prisoner caught by Carnage Maximum.  Prior to lining up the prisoners, he reveals the number of prisoners he has and his value of kill_every for the day.  Your job is to figure out which prisoner you need to be in order to survive.  Write a MATLAB script that takes the values of num_prisoners and kill_every.  The output will be survivor, which is the position of the person who survives.  If you write your script quickly enough, that person will be you.

Good luck!

Solve

Solution Stats

615 Solutions
147 Solvers

Last Solution submitted on Jun 10, 2021

Last 200 Solutions

Problem Comments

5 Comments

5 Comments

Show 2 older comments

Tim on 4 Dec 2012

I seem to get 1773 for test case 6.

@bmtran (Bryant Tran) on 4 Dec 2012

I also get 1773 for test case 6

James on 4 Dec 2012

I'll look into it a bit later on. In the meantime, that test case is deleted, so you can see if your solutions work for the rest of the test cases.

Andrew Newell on 11 Jul 2013

An interesting test case would have kill_every=1.

Elmar Zander on 27 Mar 2017

Am I the only one who finds the problem description really lacking? WTF does it mean "Because Prisoner 10 was counted during the first iteration,..." IMHO this is just blah and not a well-defined problem definition...

Solution Comments

Solution 3088591

2 Comments

2 Comments

Jimmy Sølvsteen Nielsen on 6 Oct 2020

I passed test 3 by using a WHILE loop but not a recursive function. IMHO the method should not affect the test cases but in this case it does.

Akrem Hadji on 19 Oct 2020

This is a hard one it took me a while to solve it. Thanks God Roman empire has fallen log time ago otherwise I would have no chance to escape decimation.

Solution 3088451

1 Comment

1 Comment

Jimmy Sølvsteen Nielsen on 6 Oct 2020

test 3 fails. not because of an infinite recursion in my program but owing to the lack of memory. My program is correct

Solution 1163863

1 Comment

1 Comment

bainhome on 5 May 2018

really wonderful thought!!! One of the best solution!

Solution 196399

4 Comments

4 Comments

Show 1 older comment

Ben Petschel on 21 Sep 2016

how does this work?

James on 22 Sep 2016

To paraphrase Arthur C Clarke: "Any sufficiently advanced Cody solution from Alfonso is indistinguishable from magic."

Jan Orwat on 23 Sep 2016

sdrawkcaB

Michael Cappello on 16 Sep 2018

Generalized Josephus problem

Solution 181680

1 Comment

1 Comment

Alfonso Nieto-Castanon on 25 Jan 2013

great solution! (effectively working backwards to get the initial state)

Problem Recent Solvers147

Problem Tags

carnage maximus decimate there can be only one

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