How to Calculate Area Between a Curve and Two Lines?

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N/A
N/A 2021 年 8 月 15 日
コメント済み: N/A 2021 年 8 月 16 日
Hi Everyone,
I am trying to calculate area (yellow area in attached figure) between curve and vertical and horizental axies lines. the code is provided as below. Could anyone help me?
Thank you in advance for you help.
Thank you,
clear all
clc
close all
%%
m=60;L=1;J=60;g=9.81;beta2=411.67;
KPb=2.15;KDb=0.75;
Time_Delay_Brain=0.19;
Time_Delay_Exo=0.05;
%%
for j=1:length(Time_Delay_Brain)
for jj=1:length(Time_Delay_Exo)
if Time_Delay_Exo(jj) ==0.05
n=11;
else
n=8;
end
%%
tau1=Time_Delay_Brain(j);tau2=Time_Delay_Exo(jj);
W = linspace(0, n*pi, 1000);omega=W;
Kpe=@(omega)J.*cos(omega.*tau2).*omega.^2 - KDb.*beta2.*omega.*sin(omega.*tau1 - omega.*tau2) + L.*cos(omega.*tau2).*g.*m - KPb.*beta2.*cos(omega.*tau1 - omega.*tau2);
Kde=@(omega)(omega.^2.*J.*sin(omega.*tau2) - KDb.*beta2.*omega.*cos(omega.*tau1 - omega.*tau2) + m.*g.*L.*sin(omega.*tau2) + KPb.*beta2.*sin(omega.*tau1 - omega.*tau2))./omega;
%%
D_Curve_PD_KPe=Kpe(omega);
D_Curve_PD_KDe=Kde(omega);
%%
plot(D_Curve_PD_KPe,D_Curve_PD_KDe,'color',[2*Time_Delay_Exo(jj) 2*Time_Delay_Brain(j) Time_Delay_Exo(jj) *Time_Delay_Brain(j)],'LineWidth', 0.2)
axis([0,18000,0,2500]);
hold on
end
hold on
end
plot([0 18000],[0 0],'color',[1 0 0],'LineWidth', 3)
plot([0 0],[0 2500],'color',[1 0 0],'LineWidth', 3)

採用された回答

Scott MacKenzie
Scott MacKenzie 2021 年 8 月 15 日
編集済み: Scott MacKenzie 2021 年 8 月 15 日
At the end of your code, add...
x = D_Curve_PD_KPe;
y = D_Curve_PD_KDe;
cropLogical = x > 0;
x = x(cropLogical);
y = y(cropLogical);
% define vertices of polyshape and plot
x = [0 0 x x(end) 0];
y = [0 y(1) y 0 0];
ps = polyshape(x,y);
plot(ps, 'facecolor', 'y');
% compute and output area
a1 = polyarea(x,y);
fprintf('area = %.2f\n', a1);
Output:
area = 16482962.65
  3 件のコメント
Scott MacKenzie
Scott MacKenzie 2021 年 8 月 16 日
It sounds like you want the area in region I -- with 0,0 at the bottom-left. In this case, modify my code by changing
cropLogical = x > 0 ;
to
cropLogical = x > 0 & y > 0 ;
N/A
N/A 2021 年 8 月 16 日
Thank you so much. It does work! You saved me

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