How can i simplify this

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Pablo Zarco
Pablo Zarco 2021 年 8 月 12 日
編集済み: DGM 2021 年 8 月 13 日
If (a(i)>0)&&(a(i-1)==0)&&(a(i-2)==0)&&(a(i-3)==0)&&(a(i-4)==0)&&(a(i-5)==0)&&(a(i-6)==0)...until a(i-32)==0

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回答 (2 件)

Star Strider
Star Strider 2021 年 8 月 12 日
I have no idea what you are askiing.
See if the all or any functions will work with whatever you are doing.
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DGM
DGM 2021 年 8 月 13 日
編集済み: DGM 2021 年 8 月 13 日
Like Star Strider mentioned, you can use all() or any()
a(i)>0 && ~any(a(i-32:i-1))
but there are a couple things to mention.
First is whether a is an integer class. If it's not, then testing for equality with zero is likely going to cause problems. Test to within some tolerance.
a(i)>0 && all(abs(a(i-32:i-1)-0)<tolerance)
Second is whether you're making sure a(i-32), etc exist. You may need to pad the vector or restrict the indexing accordingly.

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