How to make a function recursive in a specific position?
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I think that the best way to say what I mean is through an example.
Suppose I have a function:
y = my_func(X, n);
I want to perform the following task:
y = my_func(my_func(my_func(X, 1), 2), 3);
I wish to execute this function something like that:
y = a_wonderful_func(@my_func, 1, X, 1:3);
- The first argument is a function handle.
- The second argument indicates which argument of the function handle is made recursively.
- The leftover arguments go to the function handle. Obviously, the recursive position takes just one option as it is feedback to itself.
PS: I don't want to modify my_func. It is desirable that a_wonderful_func be a built-in function.
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回答 (1 件)
Bjorn Gustavsson
2021 年 8 月 4 日
You should have a good look at the functional-programming-constructs toolbox on the file exchange - it shows an example of how to do this (or close enough, illustrating this type of recursion on the Fibonacci-sequence). There are another functional programming package as well: functional-library. I don't work with these tools so cannot honestly recommend one over the other - you have the motivation to find out, I'm sure.
HTH
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