Can't solve parse error

4 ビュー (過去 30 日間)
Alexis
Alexis 2021 年 7 月 8 日
コメント済み: Alexis 2021 年 7 月 8 日
I am learning how to use inputParser and am stuck here:
function windowedAudio = windowAudio(audioIn,Fs,varargin)
defaultWin = 4;
defaultThresh = 0.1;
defaultRamp = 30;
defaultLong = 500;
defaultShort = 100;
p = inputParser;
addRequired(p,'audioIn',@isnumeric);
addRequired(p,'Fs',@isnumeric);
addParameter(p,'WindowLength',defaultWin,@checkWinLen);
addParameter(p,'SilenceThreshold',defaultThresh,@checkThresh);
addParameter(p,'RampLength',defaultRamp,@checkRamp);
addParameter(p,'LongSilence',defaultLong,@checkLong);
addParameter(p,'ShortSilence',defaultShort,@checkShort);
parse(p,audioIn,Fs,varargin{:});
end
It seems to run beyond that final line if I call the function with only the required arguments:
windowAudio(speechWav,Fs)
But when I try using one of the optional parameters,
windowAudio(speechWav,Fs,'WindowLength',4)
Error using windowAudio (line 31)
The value of 'WindowLength' is invalid. Not enough input arguments.
I have been Googling forever and can't figure out what I have done wrong. Can anyone with fresh eyes help me here?

採用された回答

Alek Antic
Alek Antic 2021 年 7 月 8 日
Hi,
I have reproduced your error and have found that your issue is most likely coming from your checkWinLen definition. It seems like it requires more than one argument, which is not allowed in a validation function, as documented here.
  1 件のコメント
Alexis
Alexis 2021 年 7 月 8 日
Thanks @Alek Antic, I didn't notice that in the documentation. Cheers!

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeArgument Definitions についてさらに検索

製品


リリース

R2021a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by