# Could anyone help me how to simplify the following code.

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jaah navi 2021 年 6 月 23 日
コメント済み: jaah navi 2021 年 6 月 23 日
A = cell(1,15)
B=A'
B{1}=cell(2,1)
B{2}=cell(2,1)
B{3}=cell(2,1)
B{4}=cell(2,1)
B{5}=cell(2,1)
B{6} = cell(2,2)
B{7}= cell(2,2)
B{8} = cell(2,2)
B{9}= cell(2,2)
B{10} = cell(2,2)
B{11}= cell(2,3)
B{12}= cell(2,3)
B{13}= cell(2,3)
B{14}= cell(2,3)
B{15}= cell(2,3)
in this code instead to write each and every row of the cell array separately is there any method that could be done to simplify it in the single step. For example B{1}.......B{5} are of the same size(2,1) ,B{6}.......B{10} of (2,2) , B{11}.....B{15} of (2,3) .IS it possible to write all the lines in a single step.
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KSSV 2021 年 6 月 23 日
Why you are bothered to initialize a cell in each cell in an cell array? You are missing something here.

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### 採用された回答

Mohammad Sami 2021 年 6 月 23 日
I am not sure why you are creating a nested cell array. However you can do it like this.
B = arrayfun(@(x,y)cell(x,y),ones(15,1)*2,repelem([1:3]',5,1),'UniformOutput',false)
B = 15×1 cell array
{2×1 cell} {2×1 cell} {2×1 cell} {2×1 cell} {2×1 cell} {2×2 cell} {2×2 cell} {2×2 cell} {2×2 cell} {2×2 cell} {2×3 cell} {2×3 cell} {2×3 cell} {2×3 cell} {2×3 cell}
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jaah navi 2021 年 6 月 23 日
I need another help from you.
{2×1 cell}
{2×1 cell}
{2×1 cell}
{2×1 cell}
{2×1 cell}
{2×2 cell}
{2×2 cell}
{2×2 cell}
{2×2 cell}
{2×2 cell}
{2×3 cell}
{2×3 cell}
{2×3 cell}
{2×3 cell}
{2×3 cell}

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