Scanning signal/Storing anything other then zeros

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Sebastian Daneli
Sebastian Daneli 2021 年 6 月 14 日
コメント済み: Rik 2021 年 6 月 15 日
Hi
I have a filtered signal where the base line is zero that looks in principle like this:
[0 0 0 -1 2 -2 0 0 0 2 1 -1 0 0 0 2 3 1 0 0 0...]
I wish to scan the signal and store the structures within it in a matrix such as this one:
[-1 2 -2; 2 1 -1; 2 3 1;...]
Which is the most efficient way to do this? Can I use the find function efficiently for this?
  1 件のコメント
Rik
Rik 2021 年 6 月 15 日
Regarding your flag ("I asked this question, but realized I didn't ask the correct question that I need answered."): what do you want to happen? Should this thread be deleted just because you asked a different question from what you wanted?
If the answer didn't solve your actual problem, why did you mark it as accepted answer? You can post comments with clarifications to make sure you are making clear what you want to know.

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採用された回答

Mathieu NOE
Mathieu NOE 2021 年 6 月 14 日
hello
my suggestion / demo code :
I understand the output must be a matrix of 3 columns;
tol = eps; % set a tolerance value (very low but not zero)
a = [0 0 0 -1 2 -2 0 0 0 2 1 -1 0 0 0 2 3 1 0 0 0]; % input data
b = a(abs(a)>tol); % remove zero (below tol) data
c = (reshape(b,[],3))'; % reshape in 3 columns matrix and transpose
c =
-1 2 -2
2 1 -1
2 3 1

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