Plot 2D vector field
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Hi
I have a table T of four columns x,y,u,v,
where x and y are the coordinates
and u and v are the values of the x and y components, respectively.
Thus, T represents a two-dimensional vector field.
For example, let
T=
1 3 -1 -1
1 4 0.500000000000000 -0.500000000000000
2 3 -0.250000000000000 0.250000000000000
2 4 0.100000000000000 0.100000000000000
I want to plot a 2-D vector field from this table!!!
I tried using the function:
coneplot(T)
but became the following error message:
??? Error using ==> coneplot>parseargs at 365
Wrong number of input arguments.
Error in ==> coneplot at 64
[x y z u v w cx cy cz s color quiv method nointerp] =
parseargs(nargs,args);
It seems that coneplot works only for 3-D.
Can someone tell me how to change this command line?
Thank you
Emerson
1 件のコメント
Qiujie Meng
2019 年 4 月 2 日
移動済み: Dyuman Joshi
2023 年 12 月 6 日
This is my code:
%%%%%%%%%%%%%%%%%%
close all;clc;clear all;
velocity=load('velocity100POINTS.txt');
x=velocity(:,1);
y=velocity(:,2);
u=velocity(:,3);
v=velocity(:,4);
figure
quiver(x,y,u,v)
%%%%%%%%%%%%%%%%%%%%%
Although my file has vectors,why the figure is like that......?


採用された回答
その他の回答 (1 件)
clc
clear all
syms x y
f = input('Enter:');
p = inline(vectorize(f(1)),x,y);
q = inline(vectorize(f(2)),x,y);
x = linspace(-1,1,10);
y = x;
[X, Y] = meshgrid(x,y);
U = p(X,Y)
V = q(X,Y)
quivert(X,Y,U,V,1)
axis on;
1 件のコメント
Dyuman Joshi
2023 年 12 月 6 日
編集済み: Dyuman Joshi
2023 年 12 月 6 日
@Brijesh, how exactly does your answer answers the question asked, that too 12 years ago and with an accepted answer.
There is no function as quivert and using inline and vectorize is not recommended.
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