use evalfis to read input under a range
5 ビュー (過去 30 日間)
古いコメントを表示
Hi,
May i know is there any coding can can be use for evalfis to read input under range or not? For my case:
A=imread('Linggi.tif');
[m n p]=size(A)
r=A(:,:,1);
g=A(:,:,2);
b=A(:,:,3);
Y=readfis('mam.fis');
for i = 1:m,
for j = 1:n,
k=r(i,j) > 88 & r(i,j) <= 90;
l=g(i,j) > 134 & g(i,j) <= 140;
z=b(i,j) > 144 & b(i,j) <= 145;
k1=double(k);
l1=double(l);
z1=double(z);
evalfis([k1 l1 z1],Y)
end
end
I find out that the output for all the row and column read are the same, which means the inference system did not run for the input.
Is that got another method of evalfis can be use for me to use to read input that contains range?
6 件のコメント
Iman Ansari
2013 年 8 月 10 日
編集済み: Iman Ansari
2013 年 8 月 10 日
Why your inputs are logical or zero and one? Check your fuzzy system in Rule Viewer:
Y = readfis('mam.fis');
ruleview(Y)
you can enter your inputs in the lower left of the rule viewer window in the input box then press enter:
[0 0 0]
[0 1 0]
[0 0 1]
採用された回答
Iman Ansari
2013 年 8 月 10 日
編集済み: Iman Ansari
2013 年 8 月 10 日
In your code, input isn't same as [88 134 144]. They are logical (0,1):
evalfis([88 134 144])
but:
evalfis([0 1 1])
Maybe, this is what you want:
clear;
A=imread('Linggi.tif');
[m n p]=size(A);
r=A(:,:,1);
g=A(:,:,2);
b=A(:,:,3);
Y=readfis('mam.fis');
Mask = r > 88 & r <= 90 & g > 134 & g <= 140 & b > 144 & b <= 145;
k1=r(Mask);
l1=g(Mask);
z1=b(Mask);
Output = evalfis([k1 l1 z1],Y);
Result = A;
Result(Mask) = Output;
19 件のコメント
Iman Ansari
2013 年 8 月 11 日
編集済み: Iman Ansari
2013 年 8 月 11 日
I used these 3 lines for testing the code, you don't need these lines.
A1 = uint8(zeros(10,10,3));
Mask = logical(randi([0 1],10,10));
Output = rand(nnz(Mask),1)*6.5;
その他の回答 (0 件)
参考
カテゴリ
Help Center および File Exchange で Linear Programming and Mixed-Integer Linear Programming についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!