How to assign a row matrix to another row matrix

2 ビュー (過去 30 日間)
Andrea Sbaragli
Andrea Sbaragli 2021 年 5 月 11 日
コメント済み: Andrea Sbaragli 2021 年 5 月 11 日
This is my function:
function [T1,T2, T3] = dispatch(A)
T1 = zeros(size(A));
T2 = zeros(size(A));
T3 = zeros(size(A));
i=1;
j=1;
k=1;
z=1;
for i=1:height(A)
s=1;
if A {i,2}== 1; % tagID=1
for s=1:4
T1 (j,s) = (A(i,s));
s=s+1
end
j= j+1;
end
if A{i,2}== 2; % tagID=2
for s=1:4
T2(k,s) = A(i,s);
s=s+1
end
k= k+1;
end
if A{i,2}== 3; % tagID=3
for s=1:4
T3(z,s) = (A(i,s));
s=s+1
end
z= z+1;
end
i = i+1;
end
end
it returns me that error:
The following error occurred converting from table to double:
Undefined function 'double' for input arguments of type 'table'. To convert to numeric, use the TABLE2ARRAY function, or extract data using dot or brace subscripting.

回答 (1 件)

Jan
Jan 2021 年 5 月 11 日
編集済み: Jan 2021 年 5 月 11 日
The error message suggests:
To convert to numeric, use the TABLE2ARRAY function
Did you try this already?
In one line you write:
if A {i,2}== 1
So you decided to use the brace indexing. Then you write:
T1 (j,s) = (A(i,s))
Now you try to use the parentheses. Why?
  1 件のコメント
Andrea Sbaragli
Andrea Sbaragli 2021 年 5 月 11 日
if A {i,2}== 1 here I used these brackets because == was not supported otherwise
T1 (j,s) = (A(i,s)) here brace index returns me the same error.
Yes I have already use table2array function but it does not work.
It is strange because inside A all values are in double format..

サインインしてコメントする。

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by