for j=rr-3
for i=1:rr-1
if X(i)<=t(j) && t(j)<=X(i+1)
N{1}(j,i)=1;
else
N{1}(j,i)=0;
end
end
end
I want when the code catches N{1}(j,i)=1, then for the rest of N{1}(j,i)=0..How can I do this. I tried another ifelse and for lop but didn't work. Do you have any idea?
The program trying to catch N{1}(j,i)=1 and it does it properly.I want it to stop when N{1}(j,i)=0.

1 件のコメント

nl2605
nl2605 2013 年 7 月 19 日
I am not so sure. But isn't there a break command for it?

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 採用された回答

Jos (10584)
Jos (10584) 2013 年 7 月 19 日

0 投票

help break

その他の回答 (1 件)

David Sanchez
David Sanchez 2013 年 7 月 19 日
編集済み: Andrei Bobrov 2013 年 7 月 19 日

0 投票

break will exit the inner for-loop.
for j=rr-3
for i=1:rr-1
if X(i)<=t(j) && t(j)<=X(i+1)
N{1}(j,i)=1;
else
N{1}(j,i)=0;
break; % get out of the for-loop
end
end
end
To get out of both for-loops, you should add a flag
flag=0;
for ii=1:5
ii
if flag==1
break
end
for jj=1:6
jj
if ii==3 && jj==4
disp('broken here')
flag=1;
break;
end
end
end

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