Problem 7. Column Removal

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ricardo gunawan
ricardo gunawan 2013 年 7 月 14 日
I don't know why my answer is wrong but please tell me..
function B = column_removal(A,n)
A=A(:,[1:n-1 n+1:end]);
haha=size(A);hasil=[];
A=A';
A=A(:)';
B =A;
end
  1 件のコメント
Jan
Jan 2013 年 7 月 14 日
@ricardo: In general it is a good idea when you ask in the forum, that you explain, why you assume, that there is an error. E.g. post the complete message, if you get an error, or explain the difference between your expectations and the results. Relying of the power of the forum users to guess the problem works sometimes only.

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採用された回答

Image Analyst
Image Analyst 2013 年 7 月 14 日
Simply set that column to null to remove it:
function B = column_removal(A,n)
B = A; % Initialize.
B(:, n) = [];
Isn't that what you saw as the correct answer?
  3 件のコメント
Image Analyst
Image Analyst 2013 年 7 月 14 日
No it's not. The function terminates when
it hits the end of the file, or
it hits an "end" statement, or
it hits another "function" statement, or
it hits a "return" statement.
Jan
Jan 2013 年 7 月 14 日
@ricardo: The basics of Matlab are explained in the Getting Started chapters of the documentation. It is more efficient to read them than to ask the forum to retell it.

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その他の回答 (1 件)

Azzi Abdelmalek
Azzi Abdelmalek 2013 年 7 月 14 日
There is no error in your code. What is the expected result?
If you want to remove a column number n
A=magic(5) % Example
n=3 % column to be removed
Result=A;
Result(:,n)=[]
  3 件のコメント
Azzi Abdelmalek
Azzi Abdelmalek 2013 年 7 月 14 日
What?
Jan
Jan 2013 年 7 月 14 日
@ricardo: Neither wkwkw nor the fancy character thing is useful here. We are interested in Matlab, but not cool.

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