using discrete FT with iradon

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Matthew O'Brien
Matthew O'Brien 2011 年 5 月 25 日
Dear all,
according to the matlab documentation:
'iradon uses the filtered back-projection algorithm to perform the inverse Radon transform. The filter is designed directly in the frequency domain and then multiplied by the FFT of the projections.'
I want however to try and do the procedure using discrete FT and not fast FT. Does anyone know of how to do this?
Thanks
Matt

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Steve Eddins
Steve Eddins 2011 年 5 月 25 日
Fast Fourier transform, or FFT, refers to a family of fast algorithms for computing the discrete Fourier transform, or DFT. See these blog posts for information about different kinds of Fourier transforms and the relationships between them.
  3 件のコメント
Steve Eddins
Steve Eddins 2011 年 5 月 26 日
No. You could try the different filtering and interpolation options with iradon. However, the idea that there is a difference between a "full DFT" and what the MATLAB fft function calculates is simply incorrect.
Matthew O'Brien
Matthew O'Brien 2011 年 6 月 14 日
Hi Steve, I have identified the problem and as you say it has nothing to do with DFT and FFT. Effectively the issue is that the sinogram data i have has a constant 'background' and the actual data is very low compared to this. I can recreate the problem by simply creating a Matrix of 1's which represent the 'sinogram' if this is then inverse radon transformed you get the ring:
sino = ones(20,20);
out = iradon(sino,[],20)
imagesc(out(1:20,1:20)); figure(gcf)
I guess this is a mathematical consequence of trying to perform iradon on data which doesnt contain a real sinogram?

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