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How to change x-axis values from iteration to time?

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Khan
Khan 2021 年 4 月 26 日
コメント済み: Khan 2021 年 4 月 26 日
Hello,
I have a simple problem. I have generated a matrix called "A" (2000 by 1970). The rows of the matrix are velocity vectors while the columns represents the iteration numbers. In other words, the row vectors values are changing with iteration. A simple plot is given in the picture.
let's plot row number 277 of the given matrix,
figure (1)
plot(1:1970, A(277,:))
Now I would like to plot the same row vectors against the time (time on x-axis). The intial time is zero, final time should be 1.970 with time interval 0.001.
Can someone recomend how can I do it. Thank you.

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Walter Roberson
Walter Roberson 2021 年 4 月 26 日
dt = 0.001;
time = (0:size(A,2)-1) * dt;
plot(time, A(277,:));
Note that the final value will be 1.969 not 1.970 since your time starts at 0.
  3 件のコメント
Walter Roberson
Walter Roberson 2021 年 4 月 26 日
To get exactly 1.970 with dt 0.001 and starting from 0, you would need your A to have 1971 columns instead of 1970.
Khan
Khan 2021 年 4 月 26 日
Ok, Thank you.

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