reproduce random numbers for the third dimension

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Pooneh Shah Malekpoor
Pooneh Shah Malekpoor 2021 年 4 月 21 日
回答済み: James Tursa 2021 年 4 月 21 日
Hello
I want to generate random numbers for matrix A which has a second page(i.e. 2), whose values i am going to assign to another varaiable in my code. Though i have the rng command to reproduce the same random numbers, the very numbers in the second page do vary in every iteration..How can I regenerate the same random numbers in each iteration for the second page of my matrix A? Any idea is highly appreciated.
rng('default');
rng(1);
Nmc=200
uu=1
A=rand(Nmc,uu+1,2);
  4 件のコメント
the cyclist
the cyclist 2021 年 4 月 21 日
If I understand what you want to do correctly, it is quite simple.
% Set the seed
rng default
% Set the parameters. (I chose small Nmc for illustration)
Nmc=3;
uu=1;
% Preallocate memory for the whole array.
% (Probably only important if you are going to create many slices, or large arrays.)
A = zeros(Nmc,uu+1,2);
% Generate the first slice at random
A(:,:,1) = rand(Nmc,uu+1,1);
% Repeat the first set as the second
A(:,:,2) = A(:,:,1);
% Show the result
disp(A)
(:,:,1) = 0.8147 0.9134 0.9058 0.6324 0.1270 0.0975 (:,:,2) = 0.8147 0.9134 0.9058 0.6324 0.1270 0.0975
Pooneh Shah Malekpoor
Pooneh Shah Malekpoor 2021 年 4 月 21 日
Thanks for your reply. However, let me explain a bit more clearly. in the first itertaion (i.e. Nmc=1) , i need
(:,:,1) =
.109 .2
.323 .50
.15 .6
and
(:,:,2) =
.17 .16
.84 .91
.153 .65
Again in the second iteration(i.e. Nmc=2), i want:
(:,:,1) =
.109 .2
.323 .50
.15 .6
and
(:,:,2) =
.17 .16
.84 .91
.153 .65

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採用された回答

James Tursa
James Tursa 2021 年 4 月 21 日
If you don't want the random numbers to change from iteration to iteration, then don't regenerate them inside the loop. Calculate them once, before the loop starts, and then reuse them over and over within the loop.

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