How to open file array with fopen?

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Jacky
Jacky 2013 年 7 月 1 日
Hi, I have a list of files that look like this:
J={'File1', 'File2', 'File3'}
It is not possible to open the file using fopen this way:
for i=1:length(J)
fid=fopen('J(1)', 'r')
%Some algorithms here...
fclose(fid)
end
Is there any possible way to use fopen by using looping? It seems like it only accepts the actual file name. Please help. Thanks!

採用された回答

Jonathan Sullivan
Jonathan Sullivan 2013 年 7 月 1 日
You just need to index into J properly. J looks to be a cell array so you need to use curly brackets.
Try replacing your fopen line with this
fid = fopen(J{i},'r');
  1 件のコメント
Jacky
Jacky 2013 年 7 月 1 日
It works. I thought I did that and it it didn't work. It must be something that I missed earlier on. Thank you so much for pointing that out for me.

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その他の回答 (1 件)

Walter Roberson
Walter Roberson 2013 年 7 月 1 日

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