Terminate while loop when user hits enter
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Hi eveyone,
This is my while loop. It must end when user hits enter without entering a value . The loop allows for upto 3 successive blank entries before terminating. And, I cant get the n_points matrix to save entries without error.
How do I fix these?
Thank you for your time.
clear all
disp('Begin entering the data points')
t = 1;
x_point = input('enter x : ')
y_point = input('enter y : ')
n_points = [x_point,y_point];
while x_point ~= isempty(x_point) | y_point ~= isempty(y_point) % does not terminate immedeately when user presses enter without entering a value.
x_point = input('enter x : ')
y_point = input('enter y : ')
t = t+1
n_points(t,:) = [x_point,y_point];
end
0 件のコメント
採用された回答
Jan
2021 年 4 月 11 日
編集済み: Jan
2021 年 4 月 11 日
Avoid repeating code:
disp('Begin entering the data points')
t = 0;
while true % Infinite loop
x_point = input('enter x : ');
if isempty(x_point)
break; % Stop the WHILE loop
end
y_point = input('enter y : ');
if isempty(y_point)
break; % Stop the WHILE loop
end
t = t + 1;
n_points(t, :) = [x_point, y_point];
end
Or:
disp('Begin entering the data points')
t = 0;
ready = false;
while ~ready
x_point = input('enter x : ');
if ~isempty(x_point)
y_point = input('enter y : ');
end
if ~isempty(x_point) && ~isempty(y_point)
t = t + 1;
n_points(t, :) = [x_point, y_point];
else
ready = true;
end
end
その他の回答 (1 件)
Jonathan Clayton
2021 年 4 月 10 日
the code below looks at the number of elements that the user has inputed for that loop, and if that number is zero then the loop is broken.
if numel(x_point)+numel(y_point)==0
break
end
Add this code above n_points variable so that the empty vaibles are not added to your list.
4 件のコメント
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