How to plot graphs with the specific time domain

34 ビュー (過去 30 日間)
Jinquan Li
Jinquan Li 2021 年 4 月 7 日
コメント済み: Star Strider 2021 年 4 月 8 日
Hi, i am trying to plot 3 graphs with the specific time domian. Here's my code:
t = -2*pi:0.01:2*pi;
function y = f(t)
y = (abs(t)./t+1)/2 - 2*((abs(t-pi)./(t-pi)+1)/2) + (abs(t-2*pi)./(t-2*pi)+1)/2;
endfunction
plot(t = 0:2*pi,f(t))
title("f(t)");
plot(t = -2*pi:0,-f(-t))
title("-f(-t)");
plot(t = 0:2*pi,-f(t+pi))
title("-f(t+T)");
Here's the error i got:
Below are the results that I would like to obtain. Please help. Thanks!

回答 (1 件)

Star Strider
Star Strider 2021 年 4 月 7 日
I am not certain what you want to do.
Try this:
figure
subplot(3,1,1)
plot(t((t>=0) & (t<= 2*pi)),f(t((t>=0) & (t<= 2*pi))))
ylim([-1 1])
title("f(t)");
subplot(3,1,2)
plot(t((t>=-2*pi) & (t<=0)),-f(-t((t>=-2*pi) & (t<=0))))
ylim([-1 1])
title("-f(-t)");
subplot(3,1,3)
plot(t((t>=0) & (t<= 2*pi)),-f(t((t>=0) & (t<= 2*pi))+pi))
ylim([-1 1])
title("-f(t+T)");
hold off
Experiment to get the results you want. Remember that changes in the ‘t’ vector as the independent variable must be the same in the argument to ‘f’.
  6 件のコメント
Jinquan Li
Jinquan Li 2021 年 4 月 8 日
I see. thank you so much!
Star Strider
Star Strider 2021 年 4 月 8 日
My pleasure!

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