how to exract varying matrix data

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Ede gerlderlands
Ede gerlderlands 2013 年 6 月 18 日
I have a file X=(20,350) and i want to select the column value using a selecting a selcting matrix y= (1,350)
for i= 1:350
p(y(i),:)= X(1:y(i),:)
end
but couldn't solve the problem . any help in this regard is highly appreciated.

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Iain
Iain 2013 年 6 月 18 日
p(y(i),:)= X(1:y(i),:)
Is trying to put a y(i) by "n" matrix into a 1 by "n" matrix, which CANNOT work.
p(y(i),:)= X(y(i),:)
Is trying to put a 1 by "n" matrix into a 1 by "n" matrix, which can work, provided that "y" has enough elements.
If you define y to be a list of the ROWS you want (this is the way round you've got your code, swap the :, and y(i) round for columns):
p = zeros(size(X)); % or ones, or NaNs, or whatever else as needed.
y = [1 5 7 8 9 350];
for i = 1:numel(y)
p(y(i),:) = X(y(i),:);
end
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Ede gerlderlands
Ede gerlderlands 2013 年 6 月 18 日
thanks

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