Error due to variable size data in Matlab function block

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Luca Barbiero
Luca Barbiero 2013 年 6 月 16 日
回答済み: Stefanie Schwarz 2020 年 11 月 25 日
Hi all,
I have a problem that many others had before, so I read some discussions and references before asking the following:
I have a Matlab function block in Simulink, which would like to be a modulator. It gets as input a [nx1] frame of data and should return a an [lx1] frame, where either l=n or l = n/K, for some K which divides n.
However, the (very simplyfied extract of) code
function ak = Modulator(dataFrame,dataType)
coder.varsize('ak',length(dataFrame));
M = 4;
if dataType == 1 %input is a binary stream, bit mapping required
ak = zeros(round(length(dataFrame)/log2(M)),1);
else % input data is a stream of integer
ak = zeros(length(dataFrame),1);
end
end
Doesn't compile because
"Data 'ak' is inferred as a variable size matrix, while its specified type is something else."
Now, in line 2 I specified that it is a variable size matrix, and I also used an if/else constructor to initialize it.
To make the compiler happy, one may check the "Variable number of columns" checkbox for ak, in the Data and Ports Manager, but this turns out in a new error, because the blocks in cascade don't accept variable data, at least the ones I need, like digital filters.
Thanks for any help, Luca

採用された回答

Kaustubha Govind
Kaustubha Govind 2013 年 6 月 17 日
Since your signal changes size at run-time, configuring the MATLAB Function block to output a variable-size signal using the Ports and Data Manager is the right thing to do. If the rest of the blocks do not accept variable-size signals, then you will need to deal with that issue, perhaps by limiting yourself to blocks that do accept variable-size signals, or implementing custom blocks to do what you need.
  3 件のコメント
Kaustubha Govind
Kaustubha Govind 2013 年 6 月 17 日
Great! Thanks for posting your analysis!
Prajakta Nadgir
Prajakta Nadgir 2015 年 11 月 18 日
I had similar issue. Because 'tunable' was marked for a parameter defining size of output matrix, MATLAB was guessing the size as variable...thank you for the answer...!!!

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その他の回答 (1 件)

Stefanie Schwarz
Stefanie Schwarz 2020 年 11 月 25 日
You can also see this MATLAB Answers post for an overview and instructions with screenshots:

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