Why fopen does not accept the path when it is assigned to a variable.
古いコメントを表示
filename=['tests/testbkc/result-1/abc.txt']; fid=fopen('filename','w')
Here fid returns bigger than 3 but it does not create any file.
If I wrote the path directly into fopen then everything is okey. But I need to use variable.
what should be the type of filename? Isnt it char?
Does anybody have an idea? Thanks
採用された回答
その他の回答 (0 件)
カテゴリ
ヘルプ センター および File Exchange で Filename Construction についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!