Finding the ramp response to a transfer function

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Aleem Andrew
Aleem Andrew 2021 年 3 月 17 日
コメント済み: Mathieu NOE 2021 年 3 月 18 日
If T is the transfer function defined below, how do you find the ramp response?
G = tf(poly([-2 -3]),poly([0 -1])); T=feedback(G,1)

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Mathieu NOE
Mathieu NOE 2021 年 3 月 17 日
You can use lsim function for any input
t=0:0.01:10
slope = 2;
ramp=slope*t; % Your input signal
G = tf(poly([-2 -3]),poly([0 -1])); T=feedback(G,1); % Your transfer function
[y,t]=lsim(G,ramp,t);
plot(t,y)
  2 件のコメント
Aleem Andrew
Aleem Andrew 2021 年 3 月 17 日
Thank you for your answer. Can you use lsim for a step input? I get an error message when I do so.
t=0:0.01:10;
slope = 2;
ramp=1; % Your input signal
G = tf(poly([-2 -3]),poly([0 -1])); T=feedback(G,1); % Your transfer function
[y,t]=lsim(G,ramp,t);
plot(t,y)
Mathieu NOE
Mathieu NOE 2021 年 3 月 18 日
hello
sure, but whatever the type of input signal, its dimensions must be the same as time vector (t)
I also changed the name of the input to avoid any confusion (it's not a ramp anymore)
so this is the correct code :
t=0:0.01:10;
mystep=1*ones(size(t)); % Your input signal
G = tf(poly([-2 -3]),poly([0 -1])); T=feedback(G,1); % Your transfer function
[y,t]=lsim(G,mystep,t);
plot(t,y)

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