Comparing Values from file to cell array

I have set of data such as:

 1893  []    C:\RADIOSPOTS\AUDIO\AUDIO\1893.WAV
2514  []    C:\RADIOSPOTS\AUDIO\AUDIO\2514.WAV
3115  Maryknoll  C:\RADIOSPOTS\AUDIO\AUDIO\3115.WAV
1891  []    C:\RADIOSPOTS\AUDIO\AUDIO\1891.WAV
1890  []    C:\RADIOSPOTS\AUDIO\AUDIO\1890.WAV
3119  []    C:\RADIOSPOTS\AUDIO\AUDIO\3119.WAV
2891 Shepherd Express   C:\RADIOSPOTS\AUDIO\AUDIO\2891.WAV
1893  []    C:\RADIOSPOTS\AUDIO\AUDIO\1893.WAV

I want to get all the rows that have a number starting with "3" and save that into a new array and disregard all the other rows. I started with a for loop with an if statement nested in it that would look something like this:

for cmp=1:Row
  if strcmp (3, C(cmp))
      PSA(cmp)=C(cmp)
  else 
      nonpsa(cmp)=C(cmp)
end
end

where C is a 95x3 array holding all information, num is only the first column of C (holding only the numbers) and Row is the number of rows in C and num.

However, this doesn't detect the rows that start with '3' and saves only the first column of data in the "nonpsa" array size 1xRow.

Answer 1

[Azzi Abdelmalek]

f=fopen('tes1.txt')
line1=fgetl(f)
res=[];
k=0;
while ischar(line1)
if ischar(line1)
    res =char(res,line1)
    idx=regexp(line1,'[1-9]');
    if line1(idx(1))=='3'
        k=k+1
        out{k,1}=line1
    end
 end
line1 = fgetl(f);
end
out

Answer 2

[Andrei Bobrov]

f = fopen('yourfile.txt');
c = textscan(f,'%s', 'delimiter', '\n');
fclose(f);
c1 = regexp(c{:},'^3.*','match');
out = [c1{:}]';