Using deconv to divide vectors if the numerator has a smaller degree than the denominator

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Aleem Andrew
Aleem Andrew 2021 年 3 月 15 日
回答済み: Aghamarsh Varanasi 2021 年 3 月 18 日
When using deconv to divide two vectors the output is 0 if the numerator has a smaller degree than the denominator. Can you get the answer that is the equivalent of dividing a polynomial by another? For example, for the following program the answer would be equivalent to (s+3)/(s^3+17s^2+14s+8) rather than 0.
numg=[1 3]; deng=[1 7 14 8];
deconv(numg,deng)

回答 (1 件)

Aghamarsh Varanasi
Aghamarsh Varanasi 2021 年 3 月 18 日
Hi,
'deconv' function returns two outputs. One is the quotient, returned as a row vector. The other output is the reminder as the row vector. For example,
numg=[1 3]; deng=[1 7 14 8];
[quotient, reminder] = deconv(numg,deng)
In this code, quotient = 0; reminder = [1, 3]
Hope this helps

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