After a simulation I want to determine the limits of the axes using the relational operator ==. For example:
refTime = 0:2e-3:1.5;
t0 = 0.8;
find(refTime == t0)
this returns:
ans =
Empty matrix: 1-by-0
If I try the following in the same instance:
x = 0:10
find(x == 5)
It works and returns
ans = 6.
What could be wrong??

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Azzi Abdelmalek
Azzi Abdelmalek 2013 年 5 月 23 日
編集済み: Azzi Abdelmalek 2013 年 5 月 23 日

1 投票

Try
refTime = 0:2e-3:1.5;
t0 = 0.8;
tolerence=1e-5
find(abs(refTime-t0)<tolerence)

2 件のコメント

Esteban
Esteban 2013 年 5 月 23 日
Thanks, this works :-) But I still don't see why my approach doesn't work. By visual inspection of refTime in the workspace I can see that it has an element with value exactly equal to t0.

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