How can we plot pixel difference histogram accurately?

1 回表示 (過去 30 日間)
Omar Ali Muhammed
Omar Ali Muhammed 2021 年 3 月 8 日
回答済み: Walter Roberson 2021 年 3 月 8 日
function PDH(img1,img2)
diffImage2 = imfilter(img2, [1, -1]);
diffImage1 = imfilter(img1, [1, -1]);
minValue1 = min(diffImage1(:));
maxValue1 = max(diffImage1(:));
minValue2 = min(diffImage2(:));
maxValue2 = max(diffImage2(:));
[counts2,edge2] = histcounts(diffImage2(:));
[counts1,edge1] = histcounts(diffImage1(:));
end
problem occures when trying plotting edge against counts cause size of edges always exceeds counts by one. However,
edges1 = linspace(minValue1, maxValue1, numel(counts1)) &
edges2 = linspace(minValue2, maxValue2, numel(counts2)) solve the problrm but the shape is not clear unless achieving decimation by certain number e.g 10.
plot(edges1, counts1, edges2, counts2); % Overlapped
plot(edges1(1:10:end), counts1(1:10:end), edges2(1:10:end), counts2(1:10:end));% looks better
Is there more accurate procedure to automatically fit the gragh with proper edges scaling.
Regards

回答 (1 件)

Walter Roberson
Walter Roberson 2021 年 3 月 8 日
problem occures when trying plotting edge against counts cause size of edges always exceeds counts by one.
So plot(edge2(1:end-1), counts2) and the problem is solved.
Or use histc(), in which case the last bin will exist and will count only the values that exactly equal the upper bound of the edges.

カテゴリ

Help Center および File ExchangeAnnotations についてさらに検索

製品


リリース

R2020b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by