Find the maxima in a graph
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I know that this question has been answered a lot of times in this forum but I am a beginner in MATLAB and I was not able to find a suitable solution for myself.
here is the link for uploaded graph. The variable which I am plotting has dimensions of 2705*196. How can i find the maximum peak of the graph.
回答 (3 件)
Image Analyst
2013 年 5 月 22 日
Try this:
[maxDataValue, indexAtMax] = max(yourData);
3 件のコメント
Image Analyst
2013 年 5 月 22 日
The index value will be correct. If you say it's not, it is probably because your x axis is not in elements but in some kind of real world units. In that case you'll need a calibration factor that converts the element into real world units. You can upload your data here: http://www.mathworks.com/matlabcentral/answers/7924-where-can-i-upload-images-and-files-for-use-on-matlab-answers
Ricky
2013 年 5 月 22 日
Iain
2013 年 5 月 22 日
0 投票
[m K] = max(Variable(:)) tells you the maximum value anywhere in Variable (m), and it's index (K).
4 件のコメント
Ricky
2013 年 5 月 22 日
Iain
2013 年 5 月 22 日
The index value is correct when used as: Variable(K)
Image Analyst's approach is also correct, but assumes you want the max of each column, and his indexAtMax is also correct, when used as Variable(indexAtMax(column_number),column_number)
Image Analyst
2013 年 5 月 22 日
編集済み: Image Analyst
2013 年 5 月 23 日
He showed one dimensional data in his screenshot, not 2D data. That's why I didn't use (:). Plus the values will be the same no matter if the 1D data is a row vector or a column vector. A row vector will not give you the value of each column back - it will give you the max like you expect. If someone has a 2D matrix and want the overall matrix then (:) is correct. Of course it will also work with 1D arrays as well though it's not necessary.
Iain
2013 年 5 月 23 日
Ah - Due to the firewall I'm stuck with here, I can't see the screenshot.
José-Luis
2013 年 5 月 22 日
Sounds like you want the sub indexes (row, column) not the linear indexes.
your_data = rand(10,20);
[row col] = ind2sub(size(your_data),find(your_data == max(your_data(:))))
8 件のコメント
Image Analyst
2013 年 5 月 22 日
Ricky's data looks to me like 1D data. What does it look like to you?
José-Luis
2013 年 5 月 22 日
Sure does. But he provides some conflicting information. Rick says the variable has size (2075,196). My guess was the plot is not very informative, and that he meant to use surf() or the likes.
Oh well, if all questions were cristal clear, I guess it would take away some of the fun. It would make answering questions more efficient though, removing the guessing part.
Image Analyst
2013 年 5 月 23 日
You're right. I didn't notice that. That certainly does contradict what his plot shows.
Ricky
2013 年 5 月 23 日
Could you explain why the alternatives proposed here do not fit the bill? The data and the plot don't explain things, at least no to me. What do you mean by maxima? Image Analyst answer gives you the maximum for every column of data. Iain and me give you the maximum for the entire matrix. I cannot think of another maximum.
Image Analyst
2013 年 5 月 23 日
I haven't downloaded the data yet, but if it is a 2D array, then what are you plotting? Just one of the columns or one of the rows? Or you just plotted the whole thing and were unaware of what it would plot? What do you want to plot? A row or a column, or both, perhaps with surf() or waterfall()?
Ricky
2013 年 5 月 23 日
José-Luis
2013 年 5 月 23 日
Then you get the maximums with what Image Analyst suggested. Please look at the documentation for max().
If you want the row, columns of each column maximum, then you need to transform the linear indexes to subindexes. Please look at ind2sub().
If you want to plot a surface (2d data) then you can't use plot(). Please look at the documentation for surf(). There you will find links to similar plotting tools, that could also work.
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