confusing error message: 'Not enough input arguments'?

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Valeri Aronov
Valeri Aronov 2021 年 2 月 24 日
編集済み: Valeri Aronov 2021 年 2 月 27 日
Having:
function [f] = Simple(x)
f = (x(1)-1).^2 + (x(2)-1).^2;
end
and running:
x = lsqnonlin(Simple, [2.0, 2.0])
I am getting:
Not enough input arguments.
Error in Simple (line 2)
f = (x(1)-1).^2 + (x(2)-1).^2;
2 f = (x(1)-1).^2 + (x(2)-1).^2;
What is going on here?
  2 件のコメント
Valeri Aronov
Valeri Aronov 2021 年 2 月 27 日
Thanks, Star. It was helpful, inlike Matlab's error message ;-(
Star Strider
Star Strider 2021 年 2 月 27 日
As always, my pleasure!

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採用された回答

Star Strider
Star Strider 2021 年 2 月 24 日
With a function in that format, it is necessary to pass a function handle to lsqnonlin (or any other function that takes a function handle argument):
x = lsqnonlin(@Simple, [2.0, 2.0])
That is not the situation for anonymous functions that are already function handle objects:
Simple = @(x) (x(1)-1).^2 + (x(2)-1).^2;
x = lsqnonlin(Simple, [2.0, 2.0])
producing:
x =
1.000244655961070 1.000244655961070
See What Is a Function Handle? for details.
.

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