Hi,
I have a cell array and need to convert to array.
a = {[100, 200, 300, 400, 500], [1000, 2000, 3000, 4000, 5000], [1100,1200, 1300, 1400, 1500]};
for each set b = a(1);
I need array data like,
b = [100, 200, 300, 400, 500];
i tired cell to mat, its not working.

 採用された回答

Bjorn Gustavsson
Bjorn Gustavsson 2021 年 2 月 24 日

0 投票

If you want to extract the content of one cell simply do:
b = a{1};
If you want to merge a couple of cells into an array or matrix you can do:
B2 = cell2mat(a([1 3]));
B3 = cell2mat(a([1,3])');
HTH

7 件のコメント

Chandan Prakash
Chandan Prakash 2021 年 2 月 24 日
Hi Bjorn,
if i use b = a{1}; i get single cell as output i need as a array [100, 200, 300, 400, 500];
please suggest
Bjorn Gustavsson
Bjorn Gustavsson 2021 年 2 月 24 日
Try my suggestion before re-asking for what my solution provides:
>> a = {[100, 200, 300, 400, 500], [1000, 2000, 3000, 4000, 5000], [1100,1200, 1300, 1400, 1500]}
a =
1x3 cell array
{1x5 double} {1x5 double} {1x5 double}
>> b = a{1}
b =
100 200 300 400 500
The values in b are now the contents of the first cell, which were identical to your requested array of [100, 200, 300, 400, 500].
If that doesn't solve your question you'll have to be more specific.
Chandan Prakash
Chandan Prakash 2021 年 2 月 24 日
Hi,
I tried the way as shown above and its work,
but for the data i have i'm getting result as char array in a single cell.
thank you.
Bjorn Gustavsson
Bjorn Gustavsson 2021 年 2 月 24 日
That, then, is because your data is not in the format you indicated. That must, and now you're forcing me to guess, be because the contents in cell 1 in your real array a is a string? If that is the case you have to investigate yourself, since we are not privy to that information. If that is the case you will have to convert the string to an array of numbers. This is a task completely different from extracting the information in a cell, but you can do something like:
b_string = '100 200 300 400 500';
b = str2num(b_string)
HTH
Chandan Prakash
Chandan Prakash 2021 年 2 月 24 日
Hi Bjorn,
Thank you so much, its working.
earlier i was trying using str2mat it was not working.
Regards
chandan
Bjorn Gustavsson
Bjorn Gustavsson 2021 年 2 月 24 日
You're welcome.
The reason was that you confused the two different indexings on cell-arrays, and then the data-format in the cell. When runing into these problems look at the data-type of the intermediate variables - that should reveal some of the reasons for the results or errors you get - for this I typically use (in your example):
whos b
That will tell the size and data-type of the variable b.
Chandan Prakash
Chandan Prakash 2021 年 2 月 24 日
OK, thank you for good explanation.

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その他の回答 (1 件)

KSSV
KSSV 2021 年 2 月 24 日
編集済み: KSSV 2021 年 2 月 24 日

1 投票

iwant = reshape(cell2mat(a),[],length(a))' ;
iwant(1,:)

3 件のコメント

Chandan Prakash
Chandan Prakash 2021 年 2 月 24 日
Hi KSSV,
i'm getting data in a single cell, char array.
I need it as [100, 200, 300, 400, 500];
KSSV
KSSV 2021 年 2 月 24 日
a = {[100, 200, 300, 400, 500], [1000, 2000, 3000, 4000, 5000], [1100,1200, 1300, 1400, 1500]};
iwant = reshape(cell2mat(a),[],length(a))' ;
iwant(1,:)
ans = 1×5
100 200 300 400 500
Chandan Prakash
Chandan Prakash 2021 年 2 月 24 日
Hi,
Yeah i tired the way you suggested it works,
but for the data i have i'm getting result as char array in a single cell.
Thank you.

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