Simple Solver-type function

5 ビュー (過去 30 日間)
Julia
Julia 2011 年 5 月 16 日
I am new to MATLAB and was wondering if someone could help me with a simple function. The idea is as follows:
I have two equations:
r_u = r0 + theta*delta + sigma*sqrt(delta)
r_d = r0 + theta*delta - sigma*sqrt(delta)
I need to find theta such that the above equations are satisfied as well as the equation below:
P = exp(-r0*delta)[0.5*exp(-r_u*delta) + 0.5*exp(-r_d*delta)]*100.
r0, delta, sigma and P are known. I need the function to calculate theta, r_u and r_d such that the above equations are true. I can do it in Excel using Solver but MATLAB is new to me and I would really appreciate any help I can get.

採用された回答

Matt Tearle
Matt Tearle 2011 年 5 月 16 日
If you have Optimization Toolbox, you can use fsolve. Rewrite the three equations in the form F(x) = 0, where x is a vector of your three unknowns.
% set values
r0 = rand;
delta = rand;
sigma = rand;
P = rand;
% make function
f = @(x) [r0 + x(3)*delta + sigma*sqrt(delta) - x(1);
r0 + x(3)*delta - sigma*sqrt(delta) - x(2);
exp(-r0*delta)*(0.5*exp(-x(1)*delta) + 0.5*exp(-x(2)*delta))*100 - P];
% initial guess
x0 = rand(3,1);
% find solution
x0 = fsolve(f,x0)
Here, x(1) is r_u, x(2) is r_d, x(3) is theta.
EDIT TO ADD Having looked more closely at the math, I realized that you don't even need fsolve. The problem can be reduced to a single equation in one variable (theta):
% set values
r0 = rand;
delta = rand;
sigma = rand;
P = rand;
% make functions
r_u = @(theta) r0 + theta*delta + sigma*sqrt(delta);
r_d = @(theta) r0 + theta*delta - sigma*sqrt(delta);
f = @(theta) exp(-r0*delta)*(0.5*exp(-r_u(theta)*delta) + 0.5*exp(-r_u(theta)*delta))*100 - P;
% initial guess
theta0 = rand;
% find solution
theta0 = fzero(f,theta0)
r_u(theta0)
r_d(theta0)
  2 件のコメント
Julia
Julia 2011 年 5 月 16 日
My God, it's rediculously simple. Thank you very much for your help.
Matt Tearle
Matt Tearle 2011 年 5 月 16 日
Wait until you see what happens when I actually think for a moment. See the above edit...

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeMathematics についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by