Hi guys,
I'm now learning about estimating transformation between two images.
I started to learn it from here:
It's really nice actually. I can get this picture, and also I can define the translation, rotation, and its scale.
My question is, is it possible to define the translation of each point?
or at least, can I get the xy-coordinate of each point?
I've tried to read the explanation of detectSURFFeatures from here, http://www.mathworks.co.jp/jp/help/vision/ref/detectsurffeatures.html
Unfortunately, I still don't understand how to define its coordinate.
Can someone teach me about this?
Thank you, Gibran

回答 (1 件)

Anand
Anand 2013 年 5 月 10 日

1 投票

The SURFPoints object contains a data member called Location, which contains the co-ordinate of the point.
For example, in the original image, the first matched feature is located at
>> matchedOriginal(1).Location
ans =
139.7482 95.9542
This is matched to the feature in the distorted image located at
>> matchedDistorted(1).Location
ans =
119.7571 101.1530
I don't understand your question about translation. The distorted image was obtained by rotating and scaling the original image, so there is no translation involved.
Hope this helps.

3 件のコメント

Ismail
Ismail 2014 年 9 月 4 日
Hi, At last I got the locations. Many many thanks.
Ismail
Afzal wasiullah
Afzal wasiullah 2017 年 10 月 29 日
Hi,can i know how to define 119.7571 101.1530 as x-coordinate and y-coordinate
Sadettin Durmus Talipoglu
Sadettin Durmus Talipoglu 2018 年 11 月 8 日
Hi Anand, I have been struggling the same problem. How to define outputs (interest point) of SURF and the other descripters Location ? I am trying to get interest points using canny edge filtered image for input of extractFeatures function. But I can't get location of canny filtered image like detectSURFFeatures output. I hope you can understand my question. Thanks in advance.

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