Array computation in Matlab

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Telema Harry
Telema Harry 2021 年 2 月 10 日
コメント済み: KSSV 2021 年 2 月 10 日
Please i need help in writing this code. My other option is to write the code manually. But I figured that would not be efficient. as it will involve several variables.
N is a 1 X 11 row vector
N(1) = 10, N(2) = 10, N(3) = 100, ....... N(11) = 100000
n(1) = 0:1: N(1)-1;
n(2) = 0:1:N(2) - 1; .... n(11) = 0:1:N(11) - 1;
Then I want to use this variables for my computation. For example
X(1) = cos (2*pi*n(1)./N(1)),
all the way to
X(11) = cos (2*pi*n(11)./N(11)),
I have not figured how to create an array for this operation, since n have different.
My goal is to comput values of X at the different values and compare the computational time.

回答 (1 件)

KSSV
KSSV 2021 年 2 月 10 日
Check the below example:
theta = [0 30 45 60 90 180] ; % angle in degrees
y = sind(theta)
  2 件のコメント
Telema Harry
Telema Harry 2021 年 2 月 10 日
Thank you for the feedback. However, My problem is different. My case is stated below.
n(1) = 0:1:30, n(2) = 0:1:45, n(3) = 0:1:60.
y(1) = sind(theta(1)*n(1))
y(2) = sind (theta(2)*n(2))...........
KSSV
KSSV 2021 年 2 月 10 日
What is there? According to your equation always n(1)..n(11) is zero.
Read about linspace, meshgrid.

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