# How would you automate this code?

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Armando MAROZZI 2021 年 2 月 9 日
コメント済み: Armando MAROZZI 2021 年 2 月 9 日
I have the following situation:
d = [3 39 54 53 6];
n = 103;
What I would like to do is to have a code where: when the sum of the elements in d is bigger than n, then I subtract one from the first column in d that is equal or bigger than n.
In the example above, I would have:
d = [3 39 54 *52* 6];
% since the first column where sum(d) is bigger than n is the fourth column, therefore I subtract 1 from 52
How can I automate this?
Thanks!

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### 採用された回答

Rik 2021 年 2 月 9 日
Th cumsum and find functions should be useful. Let me know if you have trouble implementing it.
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Rik 2021 年 2 月 9 日
You're welcome.
Loops are an excellent first step. Matlab is good at optimizing code that is easy to interpret. Loops are the best choice if there isn't a direct function available. Using cellfun (except for the legacy syntax) or arrayfun only hides the loop and tends to have worse performance.
Armando MAROZZI 2021 年 2 月 9 日
thanks for the tip!

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