loop with uniform distribution

Hi

Let u(i) is uniform distribution in (0,1), with size (1 column contain 10 number), and the values of u(i) is different in every loop.since the values of u(i) is random uniform distribution will take any values in (0,1).

I want

the RESULT of t3 must contain 15 column ,and every column contain 10 number, with the values of u(i) is different in every i=1:15

this is my try ,what I change to get the above RESULT.

thanks a lot for any help.

sz = [10 1];

a=1.778;

for i=1:15

u(i) = unifrnd(0,1,sz)

t1=1 - u(i);

t2=t1/a;

t3=exp(t2);

end

t3

Answer 1

[weikang zhao]

1. for loop is unnecessary;
2. Wrong way to index matrix u;
3. t1 is unnecessary cause t1 have the same probability distributions with u;

you can get t3 by:

t3=exp(unifrnd(0,1/1.778,10,15));

[hasan s]

thanks a lot for your help.

if possible , I need it as loop ...by using for...end

thank you very much

[hasan s]

I want to save the values of t3 ,

I try use

save t3

but when I close matlab and open it again....and recall the values t3 in another program ...will need to run the first program again to find t3..and the values will change since it is random

how I save the values t3 for ever.