How to get tau for every c and plot a c vs tau graph

How to get tau for every c from the equation "tau=acos(((omega^2*(D1-A*B)-C*D1)/(B^2*omega^2+D1^2))/omega)" where A, B, C, D1, omega, x, y depends on c.
clc
clear
close all
r=3.3;
K=898;
alpha=0.045;
d=1.06;
h=0.0437;
theta=0.215;
for c=.1:.1:.9
x=d/(alpha*(theta - d*h)*(1 - c));
y=r*(K-x)*(1+alpha*h*x*(1-c))/(1 - c)*K*alpha;
A=r*d*(alpha*K*h*(1-c)-1-2*alpha*h*(1-c)*x)/(alpha*theta*K*(1-c))-d;
B=d;
C=-r*d^2*(alpha*K*h*(1-c)-1-2*alpha*h*(1-c)*x)/alpha*theta*K*(1-c);
D1=r*d^2*(alpha*K*h*(1-c)-1-2*alpha*h*(1-c)*x)/x*theta*K*(1-c)+r*d^2*(K-x)/alpha*K*theta*(1-c)*x;
omega=sqrt(((A^2-B^2-2*C)+sqrt((A^2-B^2-2*C)^2-4*(C^2-D1^2)))/2);
tau=acos(((omega^2*(D1-A*B)-C*D1)/(B^2*omega^2+D1^2))/omega);
plot(c,tau)
end

 採用された回答

Iman Ansari
Iman Ansari 2013 年 4 月 16 日

1 投票

Hi
clc
clear
close all
r=3.3;
K=898;
alpha=0.045;
d=1.06;
h=0.0437;
theta=0.215;
i=1;
for c=.1:.1:.9
x=d/(alpha*(theta - d*h)*(1 - c));
y=r*(K-x)*(1+alpha*h*x*(1-c))/(1 - c)*K*alpha;
A=r*d*(alpha*K*h*(1-c)-1-2*alpha*h*(1-c)*x)/(alpha*theta*K*(1-c))-d;
B=d;
C=-r*d^2*(alpha*K*h*(1-c)-1-2*alpha*h*(1-c)*x)/alpha*theta*K*(1-c);
D1=r*d^2*(alpha*K*h*(1-c)-1-2*alpha*h*(1-c)*x)/x*theta*K*(1-c)+r*d^2*(K-x)/alpha*K*theta*(1-c)*x;
omega=sqrt(((A^2-B^2-2*C)+sqrt((A^2-B^2-2*C)^2-4*(C^2-D1^2)))/2);
tau(i)=acos(((omega^2*(D1-A*B)-C*D1)/(B^2*omega^2+D1^2))/omega);
i=i+1;
end
plot(.1:.1:.9,tau)

5 件のコメント

Atom
Atom 2013 年 4 月 16 日
Thank you Ansari. Would you please suggest me why the above programme does not produce any plot.
Iman Ansari
Iman Ansari 2013 年 4 月 16 日
編集済み: Iman Ansari 2013 年 4 月 16 日
In each loop it plot a dot, but you don't use hold on so the graph reset each loop. If using hold on and marker to better see the result:
clc
clear
close all
r=3.3;
K=898;
alpha=0.045;
d=1.06;
h=0.0437;
theta=0.215;
for c=.1:.1:.9
x=d/(alpha*(theta - d*h)*(1 - c));
y=r*(K-x)*(1+alpha*h*x*(1-c))/(1 - c)*K*alpha;
A=r*d*(alpha*K*h*(1-c)-1-2*alpha*h*(1-c)*x)/(alpha*theta*K*(1-c))-d;
B=d;
C=-r*d^2*(alpha*K*h*(1-c)-1-2*alpha*h*(1-c)*x)/alpha*theta*K*(1-c);
D1=r*d^2*(alpha*K*h*(1-c)-1-2*alpha*h*(1-c)*x)/x*theta*K*(1-c)+r*d^2*(K-x)/alpha*K*theta*(1-c)*x;
omega=sqrt(((A^2-B^2-2*C)+sqrt((A^2-B^2-2*C)^2-4*(C^2-D1^2)))/2);
tau=acos(((omega^2*(D1-A*B)-C*D1)/(B^2*omega^2+D1^2))/omega);
plot(c,tau,'MarkerSize',15,'Marker','.')
hold on
end
Atom
Atom 2013 年 4 月 16 日
Thank you very much. I have ignored that. Thank you again. Mr Ansari, would you please suggest me how to get a continuous line instead of getting dotted plots. Note that I have modified the code as per your suggestion as
clc
clear
close all
r=3.3;
K=898;
alpha=0.045;
d=1.06;
h=0.0437;
theta=0.215;
for c=.1:.001:.9
x=d/(alpha*(theta - d*h)*(1 - c));
y=r*(K-x)*(1+alpha*h*x*(1-c))/(1 - c)*K*alpha;
A=r*d*(alpha*K*h*(1-c)-1-2*alpha*h*(1-c)*x)/(alpha*theta*K*(1-c))-d;
B=d;
C=-r*d^2*(alpha*K*h*(1-c)-1-2*alpha*h*(1-c)*x)/alpha*theta*K*(1-c);
D1=r*d^2*(alpha*K*h*(1-c)-1-2*alpha*h*(1-c)*x)/x*theta*K*(1-c)+r*d^2*(K-x)/alpha*K*theta*(1-c)*x;
omega=sqrt(((A^2-B^2-2*C)+sqrt((A^2-B^2-2*C)^2-4*(C^2-D1^2)))/2);
tau=acos(((omega^2*(D1-A*B)-C*D1)/(B^2*omega^2+D1^2))/omega);
plot(c,tau,'MarkerSize',15,'Marker','.')
hold on
end
xlabel('c');
ylabel('tau');
Iman Ansari
Iman Ansari 2013 年 4 月 16 日
To plot continuous you need to have two value in each loop for plotting a line. I used tau_0 and c_0 to store previous position in each loop:
clc
clear
close all
r=3.3;
K=898;
alpha=0.045;
d=1.06;
h=0.0437;
theta=0.215;
for c=.1:.001:.9
x=d/(alpha*(theta - d*h)*(1 - c));
y=r*(K-x)*(1+alpha*h*x*(1-c))/(1 - c)*K*alpha;
A=r*d*(alpha*K*h*(1-c)-1-2*alpha*h*(1-c)*x)/(alpha*theta*K*(1-c))-d;
B=d;
C=-r*d^2*(alpha*K*h*(1-c)-1-2*alpha*h*(1-c)*x)/alpha*theta*K*(1-c);
D1=r*d^2*(alpha*K*h*(1-c)-1-2*alpha*h*(1-c)*x)/x*theta*K*(1-c)+r*d^2*(K-x)/alpha*K*theta*(1-c)*x;
omega=sqrt(((A^2-B^2-2*C)+sqrt((A^2-B^2-2*C)^2-4*(C^2-D1^2)))/2);
tau=acos(((omega^2*(D1-A*B)-C*D1)/(B^2*omega^2+D1^2))/omega);
if c>0.1
plot([c_0 c],[tau_0 tau])
end
tau_0=tau;
c_0=c;
hold on
end
xlabel('c');
ylabel('tau');
Atom
Atom 2013 年 4 月 16 日
Thank you Mr Ansari. Your work helps me a lot. Thank you. Hope I will get help from you in future.

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